A pipe can fill a tank in 20 minutes. While another pipe can drain the tank in 60 mins. If both of them are opened simultaneously, then how long it will take to full the tank?
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Answers
Solution__☺️
Assum, Pipe A & B
Pipe A fills the tank in 20 minutes, therefore each minute 1/20 of the tank is filled.
Pipe B fills the tank in 60 minutes, therefore each minute 1/30 of the tank is filled.
Combined, you may add 1/20 and 1/60 of the tank filled per minute.
=1/20 + 1/60
= 3+1/60
= 4/60 of the tank per minute.
= (4/60)× x minutes = 1 tank
= x minutes= 1/(4/60)
= x minutes= 60/4 = 15
The tank is filled in 15 minutes.
HOPE IT HELP✓✓
The time taken to fill the tank completely = 115 min
Given:
A pipe can fill a tank in 20 minutes
Another pipe can drain the tank in 60 mins.
To find:
If both of them are opened simultaneously, then how long it will take to full the tank?
Solution:
A pipe can fill a tank in 20 minutes
Another pipe can drain the tank in 60 mins
Let 60 liters be the volume of tank [ ∵ LCM (20, 60) = 60 ]
From given data A pipe can fill a tank in 20 minutes
⇒ The part of tank can be filled in 1 min = 60/20 = 3 liters
Another pipe can drain the tank in 60 mins
⇒ The part of tank can be drained in 1 min = 60/60 = 1 liter
One pipe will fill 3 liters of tank, while another pipe will drain 1 liter
⇒The part of tank can be filled in 2 min = 3 liters - 1 liter = 2 liters
In 2 min 2 liters of tank can filled
The time taken to fill 57 liters = 2×57 = 114 mins
In Last min First tank will completely fill the tank
The time taken to fill the tank completely = 114+1 = 115 min
The time taken to fill the tank completely = 115 min
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