Question

a pipe can fill a tank in 4 hour due to a tiny hole in the tank the water flows and so it takes 6 hour to fill the tank if the tank is filled in how much time will the tank get emptied because of the hole ?​

Answer 1

Answer:

12 hours.

Step-by-step explanation:

A pipe can fill a tank in 4 hours, but due to tiny hole it takes 6 hours to fill the tank.

Here..

Rate of filling tank = 1/4

Time taken because of leakage = 1/6

We have to find the time in which the tank get empited because of hole in the tank.

Now,

Rate of leakage = Rate of filling tank - Time taken because of leakage to fill the tank

i.e

• Rate of filling tank = $\frac{1}{4}$
• Time taken because of hole = $\frac{1}{6}$

Substitute the known values in above formula

⇒ $\dfrac{1}{4}\:-\:\dfrac{1}{6}$

LCM of 4 and 6 is 12.

⇒ $\dfrac{3\:-\:2}{12}$

⇒ $\dfrac{1}{12}$

⇒ $\bold{12}$ hrs.

∴ In 12 hrs. tank get empited because of hole.

Answer 2

Answer:

12 hours

Step-by-step explanation:

Step-by-step explanation:

A pipe can fill a tank in 4 hours, but due to tiny hole it takes 6 hours to fill the tank.

Here..

Rate of filling tank = 1/4

Time taken because of leakage = 1/6

We have to find the time in which the tank get empited because of hole in the tank.

Now,

Rate of leakage = Rate of filling tank - Time taken because of leakage to fill the tank

i.e

Rate of filling tank = \frac{1}{4}

4

1

Time taken because of hole = \frac{1}{6}

6

1

Substitute the known values in above formula

⇒ \dfrac{1}{4}\:-\:\dfrac{1}{6}

4

1

−

6

1

LCM of 4 and 6 is 12.

⇒ \dfrac{3\:-\:2}{12}

12

3−2

⇒ \dfrac{1}{12}

12

1

⇒ \bold{12}12 hrs.

∴ In 12 hrs. tank get empited because of hole.