A pipe can fill a tank in 4 hours, while a leak which is at one-fourth the height of the tank can empty upto that part in 2 hours. If both are operated simultaneously and initially the tank is full, then when will it be one-fourth full
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Answer:
for one part of tank take time to full is 4hours
then for 1/2part of tank take time to full is 3hours
then for 1/3part of tank take time to full is 2hours
then for 1/4part of tank take time to full is 1hour
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Answer:
6
Step-by-step explanation:
The pipe(P) takes 4 hours to fill the tank
Lets assume capacity of tank as 40L, that means rate of P is 10/hour
Now, The leak is at 1/4th the height of tank, and it can empty 1/4th of volume, i.e. 10L in 2 hours =>which means rate of leak(L) is -5/hour
Combined rate of pipe and leak is 5/hour
Now, initially the tank is full, i.e. at 40L
It has to come down to 1/4th capacity, i.e. 10L
Therefore to empty 30L at the combined rate of 5/hour would be 30/5=6hours
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