Question

A pipe can fill a tank in 5 h, while another pipe can empty it in 6 h. If both
the pipes are opened simultaneously, then how much time will be taken to
fill the tank?​

Answer 1

Step-by-step explanation:

Requires time =

$\frac{1}{5} + \frac{1}{6} = \frac{11}{30} = 0.3666 \: s$

Answer 2

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Question:-

A pipe can fill a tank in 5 h, while another pipe can empty it in 6 h. If both the pipes are opened simultaneously, then how much time will be taken to fill the tank?

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Solution:-

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First pipe:-

Time take to fill the tank = 5 h

So,

in 1 hour it can fill = (1/5)

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Second pipe:-

Time take to fill the tank = 6 h

So,

in 1 hour it can fill =(1/6)

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So, time taken by both the pipes to fill the tank is=

$= ( \frac{1}{5} ) + ( \frac{1}{6}) = \frac{1}{x} \\ = \frac{6 + 5}{30} = \frac{1}{x} \\ = x = \frac{30}{11} \\ = x = 2.7$

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Therefore, time taken by both the pipes to fill the tank is 2.7 hours.

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