Question

. A pipe closed at one end can produce
overtones at frequencies 640 Hz, 896 Hz
and 1152 Hz. Calculate the fundamental
frequency​

Answer 1

Answer:

128 Hz

Explanation:

"Fundamental frequency of an shut water pipe regarding distance T = Versus/(4L) ----------------- (1)

Ist harmonic = 3V/(4L)

2nd harmonic = 5V/(4L),

Third harmonic = 7V/(4L).. etc W

e find the distinction between any ii harmonics is usually 2V/(4L) or (V/2L)

And (1) informs us which first harmonic is actually 1/38 of their difference (Five/L)

Currently change of the best granted frequency from the following lower berth rate of recurrence is (152-896) = 256 Hz furthermore equal to = 896-640 = 256 Hz

So fundamental frequency is actually one particular/2 regarding 256 as well as 128 Hz fundamental frequency could be 128+256 = 384 Hz 2nd harmonical will be 384+256 = 640 unces,

actual granted a single.

Therefore we were provided the second 3 rd plus the quaternary harmonics and now we get examined education since 128 Hz"

Answer 2

Answer:The ans is 128Hz

Explanation:this may help you

All the best