Math, asked by salimnamira252, 4 days ago

A pipe discharges 48 litres of water per
minute into a rectangular tank of length
3.2 m and width 2.5 m. After 30 minutes,
find the height of the water in the tank.​

Answers

Answered by Johnsonmijo
1

Answer:

If 48 liters of water is discharged from a pipe in a minute into a tank of length and breadth 3.2m and 2.5 m respectively, then after 30 minutes, the height of the water in the tank is 0.18 m

Step-by-step explanation:

Given,

Liters of water the pipe discharges in a minute = 48 liters

Length of the tank = 3.2m

Width of the tank = 2.5m

After 30 minutes, the volume of the tank = amount of water in the tank

Amount of water in the tank after 30 minutes = 48* 30 = 1440 liters =\frac{1440}{1000} m^{3} = 1.44 m^{3}

So length* breadth*height =1.44 m^{3}

That is,

3.2*2.5*h=1.44\\\\h= \frac{1.44}{3.2*2.5} \\\\= \frac{0.45}{2.5} \\\\= 0.18 m

So the height of the tank after 30 minutes is 0.18 m

Answered by chandan454380
0

Answer: 0.18 m

Step-by-step explanation:

Given,a pipe discharges 48 litres of water per

minute 

And,the rectangular tank's length =3.2 m

and width =2.5 m

After 30 minutes, the amount of water discharged by the pipe =48×30=1440 liter

Let,the height of the water in the tank is X m

∴ The volume of the water in the tank=3.2×2.5×X m³=8X m³=8000X liter

Now,8000X=1440

⇒X=0.18

∴The height of the water in the tank 0.18 m

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