Question

A pipe fills a tank in 12 hous. The portion of tank filled in 9 hours is​

Answer 1

75%

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Answer 2

Answer:

Time taken by the 1st tap to fill the cistern = 12 hours

Therefore, work done by the 1 st tap in 1 hour = 1/12

Time taken by the 2nd tap to fill the cistern = 9 hours.

Therefore, work done by the 2nd tap in 1 hour = 1/9

Therefore, work done by the both taps in 1 hour = 1/12 + 1/9

= (3 +4)36

= 7/36

Therefore, both taps will fill the cistern in = 36/7 hours.

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