A pipe fills a tank in 12 hous. The portion of tank filled in 9 hours is
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Answer:
Time taken by the 1st tap to fill the cistern = 12 hours
Therefore, work done by the 1 st tap in 1 hour = 1/12
Time taken by the 2nd tap to fill the cistern = 9 hours.
Therefore, work done by the 2nd tap in 1 hour = 1/9
Therefore, work done by the both taps in 1 hour = 1/12 + 1/9
= (3 +4)36
= 7/36
Therefore, both taps will fill the cistern in = 36/7 hours.
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