a pipe is throwing water at a rate of 500 gram per second with a speed of 10 metre per second on a block of mass 5 kg on a smooth surface. find acceleration of the block
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water flown in 1sec =500gm = 1/2 kg
speed of water= 10m/s
momentum of water = mass × velocity = 1/2×10 = 5kgm/s
momentum of block = mass × velocity = 5×0 =0
total momentum of a system before and after collision is same
hence ;( momentum of block + momentum of water )before collision = (momentum of block + momentum of water )after collision
the speed of water after collision be 0 and that of block be x
5+0 = 0 + 5x
5x =5
x =5/5 m/s
x = 1m/s
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