Question

A pipe of length 85cm closed from one end. Find then number of possible natural oscillation of air column in pipe

Answer 1

4

λ =0.85

λ=4×0.85

f=v/λ= 4×0.85

340

=100Hz.

∴ Possible frequencies = nf (n is odd) = 100 Hz, 300 Hz,

500 Hz, 700 Hz, 900 Hz, 1100 Hz below 1250 Hz.