A pipe open at both ends has a fundamental frequency f in air . the pipe is dripped in water .fundamental frequency of air column now ?
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Answered by
1
Hi there
The pipe is hallow that is considered and the resonance occurs in open sides of the pipe and when it is dipped in water the resonance frequency f must be half of the original frequency in the air
Hope it will help u dear☺☺
The pipe is hallow that is considered and the resonance occurs in open sides of the pipe and when it is dipped in water the resonance frequency f must be half of the original frequency in the air
Hope it will help u dear☺☺
paridhigupta1234:
thnx it was helpful thnx a lot arvind1234 : -)
Answered by
2
HELLO PARI :- )
WE KNOW THAT = :
from open ends , fundamental frequency f in air we have
lamda /2 = > L
lambda = > 2L
v = > f lambda
f = > v/lambda = > v/2L
now we know that when the pipe is dipped vertically in water , so that half of it is water , we have
lambda / 4 = > L/2
lambda = > 2L => v = > f ' lambda
f ' = > v/lambda = > v/2 L = > f
THUS THE FUNDAMENTAL FREQUENCY OF THE AIR COLUMN IS NOW
f = > f'
HOPES THIS HELPS YOU SEE THE PHOTO I MADE IN PAINT !
@ engineer gopal khandelwal
WE KNOW THAT = :
from open ends , fundamental frequency f in air we have
lamda /2 = > L
lambda = > 2L
v = > f lambda
f = > v/lambda = > v/2L
now we know that when the pipe is dipped vertically in water , so that half of it is water , we have
lambda / 4 = > L/2
lambda = > 2L => v = > f ' lambda
f ' = > v/lambda = > v/2 L = > f
THUS THE FUNDAMENTAL FREQUENCY OF THE AIR COLUMN IS NOW
f = > f'
HOPES THIS HELPS YOU SEE THE PHOTO I MADE IN PAINT !
@ engineer gopal khandelwal
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