Physics, asked by paridhigupta1234, 1 year ago

A pipe open at both ends has a fundamental frequency f in air . the pipe is dripped in water .fundamental frequency of air column now ?

Answers

Answered by Arvind1234
1
Hi there
The pipe is hallow that is considered and the resonance occurs in open sides of the pipe and when it is dipped in water the resonance frequency f must be half of the original frequency in the air
Hope it will help u dear☺☺

paridhigupta1234: thnx it was helpful thnx a lot arvind1234 : -)
Arvind1234: Ok dear☺☺
Arvind1234: ur welcome☺
Answered by enrique
2
HELLO PARI  :- ) 
  
WE KNOW THAT = :  

from open ends  , fundamental frequency f in air we have 

lamda /2  = > L 

lambda = > 2L 

v = >  f lambda 

f = > v/lambda  = > v/2L 

now we know that when the pipe is dipped vertically in water , so that half of it is water , we have 

lambda / 4 =  >   L/2 

lambda = > 2L => v = > f ' lambda

f '  = > v/lambda = > v/2 L = > f

THUS THE FUNDAMENTAL FREQUENCY OF THE AIR COLUMN IS NOW 

f = > f'

HOPES THIS HELPS YOU SEE THE PHOTO I MADE IN PAINT ! 

@ engineer gopal khandelwal 


Attachments:

paridhigupta1234: thnx
enrique: is it correct pari ?
Arvind1234: Thats ok
paridhigupta1234: yes gopal its correct thnx for the help
Arvind1234: That is correct matgematically
enrique: yeah but dude this question was ask in jee main 2016 so i did this question in exam that time so i know about it i dont learn theories ! so i just proved it mathematically for better understanding !
enrique: np pari ask more question today i am in mood to solve hard questions !
paridhigupta1234: sure ^_^
Arvind1234: Hm
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