Question

A pipe working at full speed can fill an empty tank in 1 hour. However, it is believed that during the first hour, it was 1/12 of its normal capacity, during the second hour, during its normal capacity of 1/9, and during the third hour, it used to be 1/6 of its normal capacity. During the fourth hour, it uses 1/4 of its normal capacity, and during the fifth hour, it is its own. Uses 1/3 of normal capacity. Another pipe exhibits similar performance, but if it works at full speed, then it will fill the empty tank in two hours. With the water extracting pipes, which can be filled in a tank at 5 hours in a steady rate. If no other pipes are working, how long will it take to clear the tank by evacuation pipe at such time?

Answer 1

Answer:the long ques for 5 points no thx

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

By S D TIWARI

Let,answer is x

In 1 hr=1/x

5hr=5/x

5hr,,,,

1/12+1/9+1/6+1/4+1/3

=(3+4+6+9+12)/36

=34/36

Now, for fill tank

5hr,,,,,

( 34/36)×1/2=17/36

34/36+17/36-5/x=1

34x+17x-180=36x

15x=180

X=12

Answer = 12