Question

A pipecan fill atank in 25 min b can empty in 20 minutes.in how much time the tank will be filled

Answer 1

Here's your answer..

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Solution:-
A pipe can fill a tank in 25 min.
1 min work done by pipe A = 1/25min

B can fill a tank in 20 min.
In 1 min work done by pipe B =1/20min

So,
Together (A+ B)'s one day work =
$= > \frac{1}{20} - \frac{1}{25} \\ = > \frac{(5 - 4)}{100}$
$= > \frac{1}{100}$
Hence,
Time taken to fill tank is 100 min.
$= > 1hrs \: 40min$
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Hope it helps you...