A piston has an external pressure of 5.00 atm. How much work has been done in joules if the cylinder goes from a volume of 0.120 liters to 0.610 liters?
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Answered by
1
we know that W= P(V2-V1)
W=5(0.610-.120)
=5× 0.490
= 2.450 joul
Answered by
0
- Pext.v2-v1. 5* 0.61-0.12 =2.45
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