Question

a piston moves from rest to a speed of 5m/s in 0.04s. what are the average acceleration and distance travelled

Answer 1

acceleration=change in speed/change in time
=5/0.04=500/4=125m/s²

s=ut+1/2at²
s=0*0.04+1/2*125*0.0016
=0+0.4
0.4 m

Answer 2

Explanation:

V=U+at

5=0+a(0.04)

a=5×10²/4

a=125m/s²

V²-U²=2as

5²-0²=2×125×s

25=250s

s=25/250

=1/10

s =0.1 m