Physics, asked by Amansingh4199, 1 year ago

A piston of cross-sectional area 100 cm2 is used in a hydraulic press to exert a force of 107 dyne on the water. The cross sectional area of the other

Answers

Answered by Fatimakincsem
3

The cross sectional area of the other end is A = 1.96 x 10^4 cm^2

Explanation:

f /a = F / A

10^7 x 10^-5 / 100 x 10^-4 = 2000 x 9.8 / A

A = 100 x 10^-4 x 2000 x 9.8 / 10^2

A = 2000 x 10^-4 x 9.8

A = 19.6 x 10^-1 = 1.96 m^2

A = 1.96 x 10^4 cm^2

Thus the cross sectional area of the other end is A = 1.96 x 10^4 cm^2

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