A piston of cross-sectional area 100 cm2 is used in a hydraulic press to exert a force of 107 dyne on the water. The cross sectional area of the other
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The cross sectional area of the other end is A = 1.96 x 10^4 cm^2
Explanation:
f /a = F / A
10^7 x 10^-5 / 100 x 10^-4 = 2000 x 9.8 / A
A = 100 x 10^-4 x 2000 x 9.8 / 10^2
A = 2000 x 10^-4 x 9.8
A = 19.6 x 10^-1 = 1.96 m^2
A = 1.96 x 10^4 cm^2
Thus the cross sectional area of the other end is A = 1.96 x 10^4 cm^2
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