Question

A piston whose area is 50 cm2 moves through a distance of 30 cm against a pressure of two atmospheres. Calculate the work done in joules.​

Answer 1

#L= 3 L xx atm=304 N xx m=72,7 cal#

Explanation:

Volume of the compression:

#V= 50 cm^2 xx 30 cm = 1500 cm^3 #

equivalences

#1500 cm^3 = 1,5 dm^3 = 1,5 L = 0,0015 m^3#

Work done:

#L=P xx Delta V= 2 atm xx 1,5 L = 3 L xx atm#

#1atm = 101300 N/m^2#

#L = 3 L xx atm = 0,003 m^3 xx101300 N/m^2= 304 N xx m = 304 J#

#1 J= 0,239 cal #

#L= 304 J xx 0,239 (cal)/J=72,7 cal#