A pit 4 m long 4 m wide and 2.8 m deep is dug from a corner of a rectangular ground with dimensions 20 m
by 12 m. If the earth taken out is spread evenly over the remaining area of the ground. Find the rise in the
level of the ground.
Answers
answer:
Rise in level of ground = 0.2 m
Step-by-step explanation:
Given: Dimension of ground 20 m × 12 m
Dimension of pit which is dugged 4 m × 4 m × 2.8 m
To find : Rise in the level of ground.
Volume of Earth taken out from pit = Length × width × height
= 4 × 4 × 2.8
= 44.8 m³
volume of earth taken out = volume of earth spread
44.8 = volume of earth on ground - volume of
earth over pit
= 44.8 = 20 × 12 × h - 4 × 4 h
= 44.8 = ( 240 - 16 ) × h
= h =
= h = 0.2m
So, Rise in level ground is 0.2m
Answer:
0.2 m
Step-by-step explanation:
Rise in level of ground = 0.2 m
Step-by-step explanation:
Given: Dimension of ground 20 m × 12 m
Dimension of pit which is dugged 4 m × 4 m × 2.8 m
To find : Rise in the level of ground.
Volume of Earth taken out from pit = Length × width × height
= 4 × 4 × 2.8
= 44.8 m³
volume of earth taken out = volume of earth spread
44.8 = volume of earth on ground - volume of
earth over pit
= 44.8 = 20 × 12 × h - 4 × 4 h
= 44.8 = ( 240 - 16 ) × h
= h =
\frac{44.8}{224}22444.8
= h = 0.2m
So, Rise in level ground is 0.2m
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