Question

A pit 60 m long 40 m wide and 5 m deep was dug and the soil was spread evenly over a road of length 1 km amd breadth 24 m. What was the thickness of the soil spread? ( choose 2 correct options)
1. 50 cm
2. 5 cm
3. 0.5 cm
4. 1.5 cm ​

Answer 1

Answer:

0.5 m OR 1/2 m

Step-by-step explanation:

Volume = l * b * h

Vol. of pit = l*b*h

       = (60 * 40 * 5) m^3

Volume = 12000 m^3

Thus, Vol. of Pit = Vol. of soil spread over road

Let thickness be x

12000 = 1000 m * 24 * x

12000 / 1000 / 24 = x

1/2 m = x

Thus thickness x = 0.5 m OR 1/2 m

Answer 2

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A pit 60 m long 40 m wide and 5 m deep was dug and the soil was spread evenly over a road of length 1 km amd breadth 24 m. What was the thickness of the soil spread?

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Dimensions of pit :

Dimensions of pit :

Length of pit (L) = 60 m

Breadth of pit (B) = 40 m

Height of pit (H) = 5 m

Dimensions of road :

Length of road (l) = 1 km = 1000m

Breadth of road (b) = 24 m

Height of road (h) = ??

If the same soil of pit is spread around the road, then :

Volume of pit = Volume of cylinder

LBH = lbh

60×40×5 = 1000×24×h

12000 = 24000×h

h = 12000/24000h = 0.5 m

Height = 0.5 m

Height = 50 cm