Question

*. A pit 7 m long and 2.5 m wide is dug to a certain depth. If the volume of the earth taken out of it is 28 m³ what is the depth of the pit?​

Answer 1

GIVEN :-

• Length of Pit = 7m.

• Width of Pit = 2.5m.

• Volume of Pit / Earth taken out = 28m³

TO FIND :-

• Depth of Pit.

SOLUTION :-

We know that

Volume = Length × Breadth × Height.

Substitute the Values.

⇒ 28 = 7 × 2.5 × Height.

⇒ 28 = 17.5 × Height.

⇒ Height = 28 ÷ 17.5

⇒ Height = 1.6 m.

Therefore, Depth Of The Pit = 1.6 metres.

Answer 2

Gıѵєη :

• Length of a cuboidal pit(l) = 7m
• Breadth or width(b) = 2.5m
• Volume of the pit = 28m³

Tσ Fıηd :

• depth of the pit(height = h)

Ackησωłє∂gємєηT :

• Volume = $\large{\boxed{\sf{\orange{Length \times breadth \times height}}}}$

Sσłυтıση :

Let the depth of the pit be a.

According to the question,

$\implies{\sf{28m^{3} = 7m \times 2.5m \times a}}$

$\implies{\sf{28m^{3} = 17.5m \times a}}$

$\implies{\sf{ \dfrac{28}{17.5}= a}}$

$\implies{\sf{ 1.6m = a}}$

$\Large\implies{\boxed{\sf{\orange{ Height\:or\:Depth=1.6m}}}}$

Hence, the depth of the pit is 1.6m.

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