Math, asked by sparshsmarty05, 1 year ago

A pit is 10 m long and 2 m wide is filled with 4.8 m cubed of sand. What is the depth of the pit

Answers

Answered by Steph0303
53

Answer:

24 cm or 0.24 m

Step-by-step explanation:

Let the height of pit be 'x'

Assuming the pit to be cuboidal, we get that:

Volume of Sand present = Volume of Pit

Volume of Pit = Length × Breadth × Height

⇒ 4.8 m³ = 10 m × 2 m × x

⇒ 4.8 m³ = 20 m² × x

⇒ x = 4.8 m³ / 20 m²

⇒ x = 0.24 m or 24 cm

Hence the height is 24 cm.

Thanks !!

Answered by BrAinlyPriNcee
57
Solution:-

Let "h" be the Height of the pit.

Volume of Sand = Volume of pit = Volume of Cuboid

=> Volume of Cuboid = Length × Breadth × Height

=> 4.8m^3 = (10m × 2m × h

=> h = 4.8 m^3 /20m^2

=> h = 0.24 m

Hence, the Height of the pit is 0.24m.
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