A pit is 10 m long and 2 m wide is filled with 4.8 m cubed of sand. What is the depth of the pit
Answers
Answered by
53
Answer:
24 cm or 0.24 m
Step-by-step explanation:
Let the height of pit be 'x'
Assuming the pit to be cuboidal, we get that:
Volume of Sand present = Volume of Pit
Volume of Pit = Length × Breadth × Height
⇒ 4.8 m³ = 10 m × 2 m × x
⇒ 4.8 m³ = 20 m² × x
⇒ x = 4.8 m³ / 20 m²
⇒ x = 0.24 m or 24 cm
Hence the height is 24 cm.
Thanks !!
Answered by
57
Solution:-
Let "h" be the Height of the pit.
Volume of Sand = Volume of pit = Volume of Cuboid
=> Volume of Cuboid = Length × Breadth × Height
=> 4.8m^3 = (10m × 2m × h
=> h = 4.8 m^3 /20m^2
=> h = 0.24 m
Hence, the Height of the pit is 0.24m.
Let "h" be the Height of the pit.
Volume of Sand = Volume of pit = Volume of Cuboid
=> Volume of Cuboid = Length × Breadth × Height
=> 4.8m^3 = (10m × 2m × h
=> h = 4.8 m^3 /20m^2
=> h = 0.24 m
Hence, the Height of the pit is 0.24m.
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