Question

A pit is dug in the shape of a cuboid with dimensions 10 mx 8 m 3 m. The earth taken
Out is spread evenly on a rectangular plot of land with dimensions 40 m 30 m Wat is
increase in the level of the plot?​

Answer 1

Answer:

Volume of the pit=10×8×3metre cube=240metre cube

Area of plot=40×30m^2=1200m^2

Increase in the level of plot=1200÷240=5/m

Answer 2

Answer:

Step-by-step explanation:

Area of dug = 10 mx 8 m× 3 =240m^3

Area of dug = 10×8=80m^2

Area of field= 40m ×30m = 1200m^2

Now , area to be land spread out =

1200-80 = 1120m

So ATQ-

1120×height =volume of dug

1120m^2×h = 240m^3

h = 240/1120×100

I hope it will help you