Question

A pitot static tube having a coefficient of 0.98 used
to measure the velocity of water in a large pipe.
The stagnation pressure recorded is 3m and static
pressure 2 m. What velocity does it indicate ? (1
marks)​

Answer 1

Answer:

4.34 m/s

pitot static tube having a coefficient of 0.98 used

to measure the velocity of water in a large pipe.

The stagnation pressure recorded is 3m and static

Answer 2

Step-by-step explanation:

• So coefficient of velocity Cv = 0.98
• Stagnation pressure ꝭ1 = 3m
• Static pressure ꝭ2 = 2m
• So velocity of flow V = Cv root 2 x g x h --------1
•  So h is pressure head that is the difference of stagnation pressure and static pressure.
•                  So h = ꝭ2 - ꝭ1
•                  Or h = 3 – 2
•                    Or h = 1 m
•    Now substituting in equation 1 we get
•                                V = 0.98 root 2 x 9.8 x 1
•                                V = 4.33 m/s
• So the velocity is 4.33 m/s

Reference link will be

https://brainly.in/question/18704854