a placard is in the shape of a rhombus , whose side are 13 cm each and one of the diagonal is 24 cm . find the cost of painting both the side of the Pacard at the rate of rupees 5.50 per CM square.
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The diagonals of rhombus bisect each other at right angle.
Let ABCD is a rhombus with diagonals AC and BD which intersect each other at O.
AC = 10 cm , OA =1/2×AC=
OA= (½) × 10= 5 cm
OA= 5 cm
AB = 13 cm (given)
In ∆ AOB
By Pythagorean theorem
AB²= 0B²+ OA²
13² = OB² + 5²
169 = OB² + 25
OB²= 169 – 25
OB² =144
OB= √144
OB= 12 cm
Diagonal BD = 2 x 12= 24 cm
Hence, the length of other Diagonal = 24 cm
HOPE THIS WILL HELP YOU....
Let ABCD is a rhombus with diagonals AC and BD which intersect each other at O.
AC = 10 cm , OA =1/2×AC=
OA= (½) × 10= 5 cm
OA= 5 cm
AB = 13 cm (given)
In ∆ AOB
By Pythagorean theorem
AB²= 0B²+ OA²
13² = OB² + 5²
169 = OB² + 25
OB²= 169 – 25
OB² =144
OB= √144
OB= 12 cm
Diagonal BD = 2 x 12= 24 cm
Hence, the length of other Diagonal = 24 cm
HOPE THIS WILL HELP YOU....
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