Physics, asked by kaurpushpinder1955, 11 months ago

A plane electromagnetic wave travels in vacuum along z-direction. If the frequency of the wave is 40 MHz then its wavelength is

Answers

Answered by Anonymous
0

Answer:

The electromagnetic wave travels in a vacuum along the z-direction. The electric field (E) and the magnetic field (H) are in the x-yplane. They are mutually perpendicular.

Frequency of the wave, ν = 30 MHz = 30 × 106 s−1

Speed of light in a vacuum, c = 3 × 108 m/s

Answered by Theopekaaleader
1

id and password secret to looking good night my answer ofSolve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

Solve the following by both substitution and elimination methods.

2x - \sqrt{2} y = 0

and

 \frac{3x}{ \sqrt{2} } - y = 1

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