Math, asked by gsushsudu, 5 months ago

a plane flies 320 kmand then 250 km north.Find the shortest distance to reach its original position.

Here,OA=320km
AB=240km
OB=____________

Answers

Answered by imsraj007

1

OA=320km
AB=240km
OB= √[(320)^2+(240)^2]
= √(102400+57600)
= √160000
= √(400)^2
= 400km

gsushsudu: thanks for answering my question

imsraj007: If understood solution than Please marked as brainliest

gsushsudu: ok

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