Question

a plane flying at the height of 800m is just above one bank of river. from the point just on the opposite bank of the river,the angle of elevation of the plane is found to be 60°. find the width of the river.
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Answer 1

Given:

A plane flying at a height of 800m is just above one bank of the river. from the point just on the opposite bank of the river, the angle of elevation of the plane is found to be 60°

To find:

The width of the river

Solution:

To solve the given problem we will use the following trigonometric ratios of a triangle:

$\boxed{\bold{tan\theta =\frac{Perpendicular}{Base} }}$

Let's assume,

"AB" → the vertical height wrt ground at which the plane is flying = 800 m

"BC" → the width of the river

"∠ACB" → angle of elevation of the plane = 60°

Here,

AB = perpendicular height

BC = base

θ = 60°

∴ $tan \:60 = \frac{AB}{BC}$

$\implies \sqrt{3} = \frac{800}{BC}$

$\implies BC = \frac{800}{\sqrt{3} }$

$\implies \bold{BC = 461.88\:m}$

Thus, the width of the river is → 461.88 m.

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Answer 2

Step-by-step explanation:

Answer 9

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