A plane flying horizontally at a height of 500 m at a speed of 120 m/s wishes to hit a tank that is moving toward it on the ground with a speed of 6 m/s. At what horizontal distance from the tank should the plane release its bomb?
Answers
Answer:
1260m sure
Explanation:
using projectile motion formulas MARK ME AS BRAINLIEST PLZZZZZZ
Given height of plane (s) = 500m
Speed of plane (v) = 120 m/s
Which will also be the speed of the bomb when it is dropped..
As we know that time to reach the bomb when thrown vertically or horizontally will be the same , therefore
s = ut + 1/2 at²
s = 1/2 at² (when dropped vertically)
500 = 1/2 gt²
500 = 1/2 * 10t² [for the sake of simplicity g=10m/s²]
∴ t = 10 s
Now, horizontal range of bomb = v*t
= 120 * 10
= 1200m
It is also given that speed of tank = 6 m/s towards the plane
therefore distance covered = 6*t
= 60m
Hence, the distance at which the bomb should be thrown = 1200 + 60
= 1260m
This the answer...
I hope you understand..