Question

A plane has a take off speed of 250 m/hr what is the acceleration in m/s square of the plane if the plane start from rest and took 40sec to take off

Answer 1

⚜️ GIVEN ⚜️

Initial velocity, u = 0 m/s

(As it starts from rest)

Final velocity(Take off velocity), v = 250 m/h

Time, t = 40 s

⚜️ TO FIND ⚜️

The acceleration(a) of the plane in m/s².

⚜️ SOLUTION ⚜️

v = 250 m/h = 250 × 621 ÷ 3600

⇒ v = 43.125 m/s

We know,

$\boxed{\sf{\dag\ a=\frac{v-u}{t} }}$

Substituting the values :-

$\sf{\longmapsto a=\dfrac{43.125-0}{40} }\\\\\boxed{\boxed{\sf{\longmapsto a=1.078125\ m/s^2}}}$

Therefore, the acceleration of the plane is 1.078125 m/s².