Question

A plane has a take off speed of 88.3 m/s and require 1365m to reach that speed determine the acceleration of the plane and the time requires to reach this speed​

Answer 1

Given, initial velocity is u=0m/s

Final velocity is v=88.3m/s and traveled distance, d=1365m

Let a be the acceleration of the plane.

Using v

2

−u

2

=2ad

∴ (88.3)

2

−0

2

=2a(1365)

⟹ a=2.86m/s

2

If t be the required time.

Using v=u+at,

88.3=0+2.86t

⟹ t=88.3/2.86=30.8s

hope it helps u dear siso ✔️✔️❣️

Answer 2

Answer:

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