Question

A plane has a take off speed of 88.3 m/s and requires 1365m to each that speed. Determine the acceleration of the plane and the time required to reach this speed

Answer 1

a = u² / (2S)
= (88.3 m/s)² / (2 × 1365 m)
= 2.856 m/s²
Acceleration of plane is 2.85 m/s²

t = v / a ………[∵ v = u + at and u = 0]
= (88.3 m/s) / 2.856 m/s²
= 30.9 seconds
Time taken to reach the speed is 30.9 seconds

Answer 2

We know that v^2 = u^2 + 2as

                       (88.3)^2  = 0 + 1365 * 2 * a

                        7796.89 = 0 + 2730 * a

                         a = 2.856m/s^2 

We know that v = u + a * t

                       88.3 = 0 + 2.85 * t

                         t = 30.982 seconds.



Hope this helps!