A plane has a take off speed of 88.3m/s and requires 1365m to reach the speed. Determine the acceleration of the plane and the time required to reach the speed .
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s (distance) = 1365 m
u (Initial Velocity) = 0 m/s {it starts from rest}
v (final velocity) = 88.3 m /s
USING 3RD EQUATION OF MOTION
v square = u square + 2as
88 .3 square = 0 + 2 * 1365 * a
7796.89 = 2730 a
a = 7796.8 / 2730
=> a = 2.856 m/sec square
For time, USING 1 ST EQUATION OF MOTION
v = u + at
88.3 = 0 + 2.856t
t = 88.3 / 2.856
=> t = 30.917 secs
These are exact values you can also find by approx values
HOPE IT HELPS :):):):):)
MARK AS BRAINLIEST
u (Initial Velocity) = 0 m/s {it starts from rest}
v (final velocity) = 88.3 m /s
USING 3RD EQUATION OF MOTION
v square = u square + 2as
88 .3 square = 0 + 2 * 1365 * a
7796.89 = 2730 a
a = 7796.8 / 2730
=> a = 2.856 m/sec square
For time, USING 1 ST EQUATION OF MOTION
v = u + at
88.3 = 0 + 2.856t
t = 88.3 / 2.856
=> t = 30.917 secs
These are exact values you can also find by approx values
HOPE IT HELPS :):):):):)
MARK AS BRAINLIEST
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