A plane is flying at an height of 3000m from the ground level at an angle of elevation of 45° after a flight of 6 second the angle of elevation changes to 60°.Find the speed of the plane?
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Acc. to your figure
the speed of the plane will be 211.33 m/s
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Answer: 211.304 m/s
Step-by-step explanation:
let speed be x.
d x t = EB = 6x
in Δ DEC
tan 45 = DE/EC = 1 = 3000/ EC
EC = 3000
in Δ ABC
tan 60 = AB/BC = √3 = 3000/ BC
BC = 3000/ √3 = 1000√3 (rationalizing)
EB + BC = EC
6x + 1000√3 = 3000
6x = 3000 - 1000√3
6x = 1000√3 ( √3 - 1)
x = 1000√3( √3 - 1)/ 6
substituting √3 = 1.732
x = 211.304
therefore, the speed of the plane is 211.304 m/s.
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