Question

A plane is flying horizontally at 98 m/s and releases

an object which reaches the ground in 10 sec. The

angle made by it while hitting the ground is:

(a) 55° (b) 45° (c) 60° (d) 75°​

Answer 1

Given:-

u = 98 m/s

t = 10 sec

Solution:-

v = u + at

v = gt

v = 98m/s

therefore:-

$\theta = tan^{-1} (\frac{98}{98} )$

$\theta = 45\degree$

Thank you...