Question

A plane is flying with a constant speed along a straight line at an angle of 30
with the horizontal. The weight of the plane is 100000 N and its engine provides
a thrust of 120000 N in the direction of flight. Two additional forces are exerted
on the plane: the lift force perpendicular to the plane’s wings, and the force due
to air resistance opposite to the direction of motion. Draw the free-body diagram
showing all forces on the plane. Determine the lift force and the force due to air
resistance.

Answer 1

Answer:

The lift force on the plane is 86602.5 N and the force due to air resistance is 70000 N

Explanation:

As we know that weight of the plane makes an angle 60 degree with the motion direction

so here by force balance we can say

$mg cos 60 + F_f = F_{thrust}$

$100000 cos60 + F_f = 120000$

$50000 + F_f = 120000$

$F_f = 120000 - 50000$

$F_f = 70000 N$

Now for Lift force we can use force balance in perpendicular to the plane motion

$mg sin60 = F_{Lift}$

$F_{lift} = 100000 sin60$

$F_{lift} = 86602.5 N$

#Learn

Topic : Force balance

https://brainly.in/question/12342456