A plane is flying with a velocity of 500kmph from North-south ,in this state-
ments mangnitude is
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Answered by
2
Answer:
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Answered by
1
Explanation:
The destination is
D
=800km
j
^
where we orient axes so that +y points north and +x points east.
This takes two hours, so the (constant) velocity of the plane (relative to the
ground) is
v
pg
=(400km/h)
j
^
.
This must be the vector sum of the plane’s velocity with respect to the air which has (x,y) components (500cos70º,500sin70º),
and the velocity of the air (wind) relative to the ground
v
ag
. Thus,
(400km/h)
j
^
=(500km/h)cos70
o
i
^
+(500km/h)sin70
o
j
^
+
v
ag
which yields
v
ag
=(−171km/h)
i
^
−(70.0km/h)
j
^
.
(a) The magnitude of
v
ag
is ∣
v
ag
∣=
(−171km/h)
2
+(−70.0km/h)
2
=185km/h.
(b) The direction of
v
ag
is
θ=tan
−1
(
−171km/h
−70.0km/h
)=22.3
o
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