Question

A plane is observed to be approaching the airport. It is at a distance of 12 km from the point of observation and makes an angle of elevation of 60º. The height above the ground of the plane is

Answer 1

hope this helps you!

Answer 2

The height above the ground of the plane is 6 √3 km or about 10.39 km if   plane at a distance of 12 km from the point of observation and makes an angle of elevation of 60º

Given:

• A plane is  at a distance of 12 km from the point of observation  
• Makes an angle of elevation of 60º.

To Find:

• The height above the ground of the plane

Solution:

• The sine of an acute angle in a right triangle is the ratio of the side opposite of the angle to the hypotenuse.

Step 1:

Use sine of 60°

Sin 60° = Height above Ground / Distance from observing point

Step 2:

Substitute the Values and use Sin 60°  = √3 / 2

√3 / 2 = Height above Ground /12

=> 6 √3 = Height above Ground

=> 10.39 ≈ Height above Ground        (Using  √3 = 1.732)

The height above the ground of the plane is 6 √3 km or about 10.39 km