a plane leaves jammu at 5 a.m and reaches patna at 7:20 a.m. flying at a speed of 600 km/h. what is the distance that the plane covers
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Answered by
25
Answer:
1400km
Step-by-step explanation:
Distance= Speed×Time
Time= 2hrs20mins
= 7/3 hrs Speed given= 600km
Therefore Distance = 600×7/3
=1400km
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0
Answer:
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