A plane left 30 min late than its scheduled time and in order to reach the destination 1500 km away in time,it had to increase its speed by 100 km/hr from usual speed.find its usual speed
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Anonymous:
Hum distance ko equal mn nahi rakh sakte
waise answer ni nikal rHa
(x+1/2)(y+100)=150p
1500
aa to gya answer 500 and time equal rkha gya h friend
Are agar distance ko equal mn rahe
to bhi nikalna chahiye bt nhi nikal rha...just try once
Yahi sahi answer hai
Even I did the same
Yeh sahi hai....par agar time ko equal mai naa lekar distance ko equal mai le...to bhi answer niklalna chahiye...but nahi nikal raha...prtyusha
Answered by
8
A/q
Speed =Distance /time
=(1500/x)hrs
Time taken=(x - 1/2) Hrs
Speed = Distance / Time = 1500 / (x - 1/2) Hrs
Increased speed =100km/hr
1500 / (x - 1/2)] - [1500 / x]=100
1/(2x2 - x) = 1/6
2x2 - x = 6
x = 2 or -3/2
So,
The usual time taken by the aeroplane = 2 hrs
and the usual speed = (1500 / 2) = 750 km/hr.
Speed =Distance /time
=(1500/x)hrs
Time taken=(x - 1/2) Hrs
Speed = Distance / Time = 1500 / (x - 1/2) Hrs
Increased speed =100km/hr
1500 / (x - 1/2)] - [1500 / x]=100
1/(2x2 - x) = 1/6
2x2 - x = 6
x = 2 or -3/2
So,
The usual time taken by the aeroplane = 2 hrs
and the usual speed = (1500 / 2) = 750 km/hr.
It is wrong
Yeah
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