A plane left 30 minutes late due bad weather and in order to reach its destination , 1500 km away in time, it had to increase its speed by 100km/hr from its usual speed find the usual speed of the plane.
PLZ..URGENT NEEDED
Answers
Given:
Late = 30 min
Distance = 1500 km
Speed increase = 100 km / hr
To find:
The usual speed.
Solution:
By formula,
Speed = Distance / Time
Since the time is unknown,
Consider x for time,
Speed original = 1500 / x
Time taken = ( x - 1 / 2 )
Therefore,
Substituting the value of x,
Speed new = 1500 / (x - 1/2)
Speed New - Speed original = 100
( 1500 / ( x - 1 / 2 ) ) - ( 1500 / x ) = 100
150 ( ( 10 / x - 1 / 2 ) - 10 / x = 100
30 x -30 x +15 = 2x^2 - x
15 = 2x^2 - x
2x^2 - x -15 = 0
Solving,
x = -5/2
x = 3
As time cannot be negative,
The usual time taken by the plane is 3 hr
Speed original = ( 1500 / 3 ) = 500 km / hr
Hence, the usual speed of the plane is 500 km / hr
Read more on Brainly.in - https://brainly.in/question/3087358
Solution :-
Let the original speed of train be x km/hr
New speed = (x + 100) km/hr
We know that,
Time = Distance / Speed
Given : A plane left 30 minutes or 1/2 hours later than the scheduled time.
According to the question,
=> 1500/x - 1500/(x + 100) = 1/2
=> (1500x + 15000 - 1500x)/x(x + 100) = 1/2
=> 2(15000) = x(x + 100)
=> 30000 = x² + 100x
=> x² + 100x - 30000 = 0
=> x² + 600x - 500x - 30000 = 0
=> x(x + 600) - 500(x + 600) = 0
=> (x - 500) (x + 600) = 0
=> x = 500 or x = - 600
∴ x ≠ - 600 (Because speed can't be negative)
Hence,
Its usual speed = 500 km/hr