Math, asked by ankitachoudhary2, 1 year ago

a plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time it had to increase its speed by Handa km per hour from the usual speed find its usual speed


ankitachoudhary2: ok
neosingh: handa is?
Vikrant1927: ????
neosingh: handa km per hour
neosingh: read the ques statement
Vikrant1927: oo yaa you're right
neosingh: whats the value
ankitachoudhary2: sorry handa=100
neosingh: sure?
ankitachoudhary2: thanks

Answers

Answered by Harshbhavna
7
Hope this helps you..........
Attachments:
Answered by TheBrainliestUser
0
Solution :-

Let the original speed of train be x km/hr
New speed = (x + 100) km/hr

We know that,
Time = Distance / Speed

Given : A plane left 30 minutes or 1/2 hours later than the scheduled time.

According to the question,

=> 1500/x - 1500/(x + 100) = 1/2
=> (1500x + 15000 - 1500x)/x(x + 100) = 1/2
=> 2(15000) = x(x + 100)
=> 30000 = x² + 100x
=> x² + 100x - 30000 = 0
=> x² + 600x - 500x - 30000 = 0
=> x(x + 600) - 500(x + 600) = 0
=> (x - 500) (x + 600) = 0
=> x = 500 or x = - 600

∴ x ≠ - 600 (Because speed can't be negative)


Hence,
Its usual speed = 500 km/hr
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