A plane left 30 minutes late than its scheduled time and in order to reach the destination 1000 Km away in time it had to increase its speed by 100 Km/h from the usual speed find its usual speed
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Let the usual speed of the plane be xkm/h
New speed = (X+100)km/h
Now , difference in time = 30min
= 1000/X -1000/(X+100) = 30/60
(because time = distance /speed)
= 1000|1/X -1/X+100 = 3/6
= 1000|X+100-x/X(X+100) = 3/6
= 100000/x^2+100x= 1/2
= 200000= x^2+100x
= x^2+100x-200000
now factorise it
= x^2+500x-400x-200000
= X(X+500) -400(X + 500)
= (x-400) = 0
and (X+500) =
we get
X = 400 and X= -500
speed can't be in negative
so
X=400km/h
answer
the usual
speed of the plane is
400km/h
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