Question

A plane left 30 minutes late than its sheduled time and in order to reach thr destination 1500 km away in time it had to increase its speed by 100 km/h from the usual spesd.Find the usual speed.

Answer 1

let usual speed be x km/hr

New speed =( x+100) km/hr

According to question

time plane will take when it travels with usual speed - time plane will take when it travels with new speed = 1/2 hour

Distance = speed * time

1500 / x - 1500 /( x+ 100) = 1/2

after solving

speed will be 500 km /hr

Answer 2

Given:

Late = 30 min

Distance = 1500 km

Speed increase = 100 km / hr

To find:

The usual speed.

Solution:

By formula,

Speed = Distance / Time  

Since the time is unknown,  

Consider x for time,

Speed original = 1500 / x  

Time taken = ( x - 1 / 2 )  

Therefore,

Substituting the value of x,

Speed new = 1500 / (x - 1/2)  

Speed New - Speed original = 100

( 1500 / ( x - 1 / 2 ) ) - ( 1500 / x ) = 100

150 ( ( 10 / x - 1 / 2 ) - 10 / x = 100  

30 x -30 x +15 = 2x^2 - x

15 = 2x^2 - x

2x^2 - x -15 = 0

Solving,

x = -5/2

x = 3

As time cannot be negative,

The usual time taken by the plane is 3 hr

Speed original = ( 1500 / 3 ) = 500 km / hr

Hence, the usual speed of the plane is 500 km / hr

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