a plane left 30 minutes late then its scheduled time and in order to reach the destination 1500 km away in a time it had to increase its speed by 100 km per hour from the usual speed find its usual speed
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Hey mate..
Here's your answer..
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@Rêyaañ11
Here's your answer..
==============================
HOPE IT HELPS
@Rêyaañ11
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Answered by
6
Heya !!
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Let the usual speed of plane be x km/hr.
A.T.Q.
1500/x – 1500/(x+100) = 30/60
=>[ 1500(x+100) – 1500x] / x(x+100) = 1/2
=> 150000 / (x²+100) = 1/2
=> x²+100 = 300000
=> x²+100–300000 = 0
=> x²+600x–500x–300000 = 0
=> x(x+600) –500(x+600) = 0
=> (x–500) (x+600) = 0
=> x = 500 or x = –600
Speed can't be negative.
So, x = –600 is inappropriate.
Thus, the usual speed of the train is 500 km/hr.
==================================
Hope my ans.'s satisfactory.☺
==================================
Let the usual speed of plane be x km/hr.
A.T.Q.
1500/x – 1500/(x+100) = 30/60
=>[ 1500(x+100) – 1500x] / x(x+100) = 1/2
=> 150000 / (x²+100) = 1/2
=> x²+100 = 300000
=> x²+100–300000 = 0
=> x²+600x–500x–300000 = 0
=> x(x+600) –500(x+600) = 0
=> (x–500) (x+600) = 0
=> x = 500 or x = –600
Speed can't be negative.
So, x = –600 is inappropriate.
Thus, the usual speed of the train is 500 km/hr.
==================================
Hope my ans.'s satisfactory.☺
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