a plane left 40 minutes late due to the bad weather and in order to reach the destination 1,600 km away in time it and increase the speed of 400 km hour from its actual speed find the speed of the plane
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Given Distance = 1600 km
Let the usual speed be x km/h
now, we know that
speed = distance /time
time = distance / speed
Usual time = 1600/x
Now, due to bad weather the speed is increased b 400 km/ hr
new speed = 1600/x+400
Now it's given that the plane left 40 minutes late
new time = 1600/x+400 + 2/3 ( 40/60 = 2/3 hours)
1600/x = 1600/x+400 +2/3
1600/x-1600/x+400 = 2/3
1600(x+400)-1600x)/x(x+400) = 2/3
1600x + 640000-1600x/x²+400x = 2/3
640000 = 2/3(x²+400x)
640000 * 3/2 = x²+400x
960000 = x² +400x
0 = x²+400x-960000
0 = x² +1200x-800x-960000
0 = x( x+ 1200) - 800(x+1200)
0= (x+1200)(x-800)
x= -1200 or x= 800
Speed cannot be negative
Hence, usual speed = 800 km/h
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