Question

A plane left half an hour later than the scheduled time and in order to reach its destination 1500 kilometers away in time, it had to increase its speed by 33.33 percent over its usual speed. Find its increased speed.

Answer 1

Answer:

where is time??

as i referred to a similar qu. like this speed is750km/hr

Step-by-step explanation:

Answer 2

Answer:

The increase speed of plan from its usual speed is 999.975 kilometers per hours .

Step-by-step explanation:

Given as :

The total distance to be cover by plan = d = 1500 km

Let The usual time = t hours

The delayed time = (t - $\dfrac{1}{2}$) hours

Let the usual speed of plan = s km/h

The increased speed  = s + 33.33% of s   km/h

I.e The increased speed of plan = 1.3333 s    km/h

According to question

∵ Distance = Speed × Time

So, d = s × t

i.e s × t = 1500

And

1.3333 s × (t - $\dfrac{1}{2}$)  = 1500

Or, 1.3333 × s × t - 1.3333 × $\dfrac{1}{2}$ × s = 1500

Or, 1.3333 × 1500 - 0.6666 × s = 1500

Or, 199995 - 1500 = 0.6666 × s

Or, 0.6666 × s = 49995

∴  s = $\dfrac{49995}{0.6666}$

i.e s = 750

So, The usual speed of the plan = s = 750 km/h

The increase speed of plan = 1.3333 × s

i,e The increase speed of plan = 1.3333 × 750

Or, The increase speed of plan = 999.975 km/h

Hence, The increase speed of plan from its usual speed is 999.975 kilometers per hours . Answer