Question

A plane meets the coordinate axes in A,B,C such that the centroid of ∆ABC is at point (p,q,r) show that the equation of the plane is x/p + y/q + z/r = 3

Answer 1

A(p,0,0)
B(0,q,0)
C(0,0,r)
from the given 3 points i think u r smart enough to derive the equation of the plane...

Answer 2

The equation of the plane is

x/A+y/B+z/C=1

By the definition of the centroid

(A/3,B/3,C/3)=(p,q,r)

Therefore,

A=3p

B=3q

C=3r

The equation of the plane becomes

x/3p + y/ 3q + z/3r=1

1/3(x/p+y/q+z/r)=1

So,

x/p + y/q + z/r =3


mark as brainliest.