Physics, asked by abdullahzaki2003, 11 months ago

a plane mirror and an object approach each other with speeds of 5 metre per second and 10 M per second respectively the speed of the image will be...​

Answers

Answered by topwriters
5

Man's speed = 30 m/s

Explanation:

Let's assume that the distance of the man from the mirror is D. The image will be at a distance D behind the mirror. Distance between the man and the image is 2D.

After one secondm the man moves a distance of 5 m/s toward the mirror.

The image also moves a distance 10 m/s toward the mirror.

Distance between the man and the image is (2D – 30)

In one second the distance between the man and image has reduced by an amount = 2D – (2D –30) = 30 m.

Thus the man’s speed toward the image is 30 m/s.

Answered by varsha0709
0

Answer:

25

Explanation:

Speed of object,

u

o

=

5

m

s

1

Speed of mirror,

u

m

=

10

m

s

1

Mirror and object are approaching each other.

To find:

Speed of image

Procedure:

Let initial position of object be at

x

o

i

=

0

Let initial position of mirror be at

x

m

i

=

u

Object distance equals the image distance. Hence, initial position of image is

x

i

i

=

2

u

Distance is the product of speed and time.

After time

t

,

Position of object will be:

x

o

f

=

x

o

i

+

u

o

t

=

5

t

Position of mirror will be:

x

m

f

=

x

m

i

u

f

t

=

u

10

t

Let the final position of image be

x

i

f

Using object distance equals image distance after time

t

.

x

i

f

x

m

f

=

x

m

f

x

o

f

x

i

f

=

2

u

25

t

Distance moved by image in time

t

is:

s

i

=

x

i

f

x

i

i

s

i

=

25

t

Speed is the ratio of distance and time. Speed of the image is:

v

i

=

s

i

t

=

25

Negative sign appears because image is moving leftwards.

Hence, speed of image is

25

m

s

1

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