a plane starting frm rest move trough a acceleration of 3mper sec square and make a run of 35 sec before taking off wht is the minimum distance of the path of the run way
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Answered by
1
a=3mpsecsquare
t=35sec
s=?
u=0mpersec
s=ut+1/2*at^2
=0*35+1/2*3*35*35
=1837.5m
t=35sec
s=?
u=0mpersec
s=ut+1/2*at^2
=0*35+1/2*3*35*35
=1837.5m
anesha1:
thaxx a lot
Answered by
0
u=0
a=3m/s^2
t=35s
d=?
d=ut+1/2.at^2
d=0.35+1/2.3.35.35
d=1837.5
a=3m/s^2
t=35s
d=?
d=ut+1/2.at^2
d=0.35+1/2.3.35.35
d=1837.5
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