Question

a plane starts from rest and accelerate along the ground beforetakes off. it moves 600m in 12s. find acceleration

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\red{\boxed{\sf Acceleration (a)=8.3m/s^2}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Initial Velocity of plane (u) = 0

• Distance moved by plane (s) = 600m

• Time (t) = 12s

$\large\underline\pink{\sf To\:Find: }$

• Acceleration (a) = ?

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We know ,

$\large{\boxed{\sf s=ut+\frac{1}{2}at^2 }}$

$\large\implies{\sf 600=0+\frac{1}{2}a(12)^2 }$

$\large\implies{\sf a=\dfrac{600×2}{12×12} }$

$\large\implies{\sf a=\frac{1200}{144}}$

$\large\implies{\sf a=8.3m/s^2}$

$\red{\boxed{\sf Acceleration (a)=8.3m/s^2}}$

Answer 2

$\large\underline{\underline{\sf Given:}}$

• Plane starts from rest

•°• Initial Velocity (u) =0 m/s

• Distance Moved by plane (s) = 600m

• Time take by plane to move (t) = 12s

$\large\underline{\underline{\sf To\:Find:}}$

• Accleration of plane (a) = ?

$\large\underline{\underline{\sf Solution:}}$

According to second equation of motion :

$\large{\boxed{\sf s=ut+\frac{1}{2}at^2}}$

$\large\implies{\sf 600=0+\frac{1}{2}×a×(12)^2}$

$\large\implies{\sf a=\frac{600×2}{144}}$

$\large\implies{\sf a=8.3m/s^2}$

$\Large\underline{\underline{\sf Answer:}}$

$\large\underline{\underline{\sf Acceleration\:of\:plane\: is\:8.3m/s^2}}$