A plane takes 2 hours and 45 minutes (2.75 hours) to cover a distance between two airports. If it travels by 20 km/h slower then it takes 3 hours. Find the speed of the plane. Also find the distance between the two airports.
It is a Linear Equation sum.
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Answer:
plane takes time to cover a distance = 2.75 hr
let the speed be = x km/h
the formula of the distance is d=s*t
ATQ,
the plane takes times to cover the distance =3 hr
and the speed slower down by 20 km/h
so new speed = x-20 km/h
now we have two equation now evaluate them,
⇒x ×2.75 = (x - 20)×3
⇒2.75 x = 3x -60
⇒275x/100= 3x -60
⇒6000= 300x -275x
⇒6000÷25=x
⇒240
so distance will be 240-20*3
=660 km
Step-by-step explanation:
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